Answer to Question #179319 in General Chemistry for mel

Question #179319

calculate the standard enthalpy change for the reaction at 25*C


Mg(OH)2 (s) + 2HCl (g) -----> MgCl2 (s) + 2H2O (g)



1
Expert's answer
2021-04-11T23:53:18-0400

Mg(OH)2( s ) + 2HCl ( g ) ==> MgCl2( s ) + 2H2O(g)

Look up the ∆Hfº of reactants and products. Then ∑produts - ∑reactants = ∆Hreaction

These are the values I found:

Mg(OH)2(s) = -924.7 kJ/mol

HCl(g) = -92.5 kJ/mol

MgCl2(s) = -641.8 kJ/mol

H2O(g) = -241.8 kJ/mol


(-641.8 + 2x-241.8) - (-924.7 + -92.5) = ∆Hreaction

-1125.4 - (-1017.2) = ∆Hreaction

∆H reaction = -108.2kJ



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