Answer to Question #179186 in General Chemistry for Hashilli

General Chemistry

Question #179186

Two 2.5 kg bowling balls are 25 m apart. What is the force of gravity exerted on each bowling ball?

Expert's answer

"F_{12}=F_{21}=G\\frac{m_1m_2}{r^2}="

"=6.67\\cdot10^{-11}\\cdot\\frac{2.5\u00d72.5}{25^2}=6.67\u00d710^{-9}(N)=6.67(nN)"

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