Answer to Question #179112 in General Chemistry for sabine

Question

Calculate the wavelength (in nm) of the light radiation capable of causing an ionization energy equal to 502*J.𝑚𝑜𝑙−1

(c= 3*m/s;     h= 6.626 × J.)

Answer 1

$E= hv$

$502 = (6.626×10^{-34})v$

$v= \frac{502}{6.626×10^{-34}}=7.577×10^{35}$

$\lambda v= c$

$\lambda= \frac{c}{v}$

$\lambda=\frac{3.00×10^8}{7.577×10^{35}}=3.959×10^{42}$