Answer to Question #178642 in General Chemistry for Arsen

Question #178642


A chemist reacted 17.25 grams of sodium metal with an excess amount of chlorine gas. The chemical reaction that occurred is shown.


__Na + __ Cl2 → __ NaCl


If the percentage yield of the reaction is 88%, what is the actual yield? Show your work, including the use of stoichiometric calculations and conversion factors. 


1
Expert's answer
2021-04-07T11:29:00-0400

Given,

% yield ="\\dfrac{\\text{ Reacted Na }}{\\text{ Required Na}}\\times 10"


"88=\\dfrac{17.25}{\\text{ Required (Na)}}\\times 100"


"\\text{ Required Na}=\\dfrac{1725}{88}=19.60g"


Actual yield = "\\dfrac{\\text{ Reacted Na }}{\\text{ Required Na}}\\times 100"


"=\\dfrac{17.25}{19.60}\\times 100=88%" %



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