Calculate the number of grams of sodium chloride (NaCl) necessary to prepare 230mL of a 2.00 M aqueous sodium chloride solution. Formula mass of NaCl is 58.5 amu.
Molarity of solution =2 M=2\space M=2 M
Volume =230 mL=0.230 L=230\space mL=0.230\space L=230 mL=0.230 L
Moles of NaCl =2×0.230=0.460 mol=2\times0.230=0.460\space mol=2×0.230=0.460 mol
Mass of NaCl =0.460×58.5=26.91 g=0.460\times58.5=26.91\space g=0.460×58.5=26.91 g
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