Answer to Question #178614 in General Chemistry for Anna

General Chemistry

Question #178614

Calculate the mass of Mg needed to produce 80 mL of hydrogen gas at STP.

Expert's answer

Mg + 2H₂O "\\to" Mg(OH)₂ + H₂

80 mL (0.08L) of Hydrigen at STP

moles of H₂ produces = 0.08/22.4 = 0.00357 mol

mol of Mg required = 0.00357 mol

Mass of Mg = 0.00357×24 = 0.085 g

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