Answer to Question #178507 in General Chemistry for sam

Question

A 70.0 g piece of metal at 80.0^oC is placed in 1.0 x 10² g of water at 22.0^oC contained in a calorimeter. The metal and water come to the same temperature at 24.6^oC. How much heat (in kJ) did the metal give up to the water?

Answer 1

C_p(H₂O) = 4,18 $\frac{J}{g\times K}$

$\Delta$T(H₂O) = (24.6 - 22) = 2.6 ^oC = 2.6 ^oK

Q = 4.18$\times$2.6$\times$100 = 1086.8 J = 1.09 kJ

Answer: Q = 1.09 kJ.