Answer to Question #178367 in General Chemistry for Satyajay Mandal

Question

I had asked a question few weeks ago in General Chemistry as #164093 which says that " Suppose if I heat the products obtained on neutralising H4Cl3NO3 (1 part HNO3 and 3 parts HCl) with NaK3(OH)4 (or NaK3O4H4) {1 part NaOH and 3 parts KOH} to any temperature more (not less) than 100 degree Celsius (or 212 degree Fahrenheit) then can I get only the NaK3NCl3O3 (1 part NaNO3 and 3 parts KCl) as it is the boiling point of water or will I get it with 4H2O (as NaK3H8Cl3NO7)?" here the expert who answered it gave a general reaction theory as usual, Can you tell him to add some extra info in it like whether I get NaK3Cl3NO3 without 4H2O or whether I get NaK3Cl3H8NO7 if I heat the products obtained on neutralizing H4Cl3NO3 with NaK3(OH)4 (or NaK3O4H4) as to his reply to my query?

Answer 1

You will get NaK3Cl3H8NO7 if you heat the products obtained on neutralizing H4Cl3NO3 with NaK3(OH)4 (or NaK3O4H4)