Answer to Question #178295 in General Chemistry for Dawn L Brown

Question #178295

How many milliliters of a 14 M NH3 stock solution are needed to prepare 200 mL of a 4.2 M dilute NH3 solution


1
Expert's answer
2021-04-05T08:00:14-0400

M1 = 14M , V1 = ? , M2 = 4.2M , V2 = 200 mL

M1V1 = M2V2

14M ×V1 = 4.2M × 200mL

V1 = 60 mL


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