Answer to Question #177603 in General Chemistry for Sophia Zheng

General Chemistry

Question #177603

How many moles of Na₂CO₃ are there in 0.9 L of 1.2 M solution?

Expert's answer

C_М = n/V

n (Na₂CO₃) = C_M x V = 1.2 x 0.9 = 1.08 mol

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