Question #177339

4 mol NH3 + 5 mol oxygen gas-> 4 mol nitrogen monoxide+ 6 mol water if 172.68 grams of nitrogen monoxide are produced how many grams of water will also be produced

Expert's answer

2C_{8}H_{18}+25O_{2}-->16CO_{2}+18H_{2}O

moles C8H18 used"= 25.1g \u00d7\\frac{1 mole}{114 g} = 0.220moles"

Assuming complete combustion, you can now figure out how many moles of CO_{2}Â are produced, since the equation tells you that 2 moles C_{8}H_{18}Â produces 16 moles CO_{2}.

Â

moles CO_{2}Â producedÂ "=0.220 \u00d716"

moles CO_{2}/2 moles C_{8}H_{18}Â "=\\frac{0.220 \u00d716}{2}=1.76moles"Â of CO_{2}Â are produced

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