Answer to Question #177309 in General Chemistry for hayley farah

Question

How many moles of barium hydroxide, Ba(OH)₂, are present in 200.5  g?

     mol Ba(OH)₂   

How many moles of barium ions are present in Part 1?

     mol Ba²⁺   

How many moles of hydroxide ions are present in Part 1?

     mol OH^1-   

Answer 1

Part I

Molar mass Ba(OH)2 = (137.327+2(16)+2(1.008))g

Ba(OH)2 = 171.34g

Therefore : 1 Mol = 171.343g

? = 235.5g

= (235.5/171.343) = 1.4Moles

PART II

1 mol of Ba+ = 137.327

? = 171.343

=1.2moles

PART III

1.4 moles = 2mol

? = 1 mol

(1.4/2) =0.7 moles