What mass of precipitate (in g) is formed when 58.2 mL of 0.500 M FeCl₃ reacts with excess AgNO₃ in the following chemical reaction?
FeCl₃(aq) + 3 AgNO₃(aq) → 3 AgCl(s) + Fe(NO₃)₃(aq)
Mass of precipitate =2.37g
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