Question #176783

If it takes 0.5 L of oxygen gas kept in a cylinder under pressure to fill an evacuated 4.50 L vessel in which the pressure is 0.98 atm, what was the initial pressure of the gas in the cylinder?

Expert's answer

Volume of oxygen "V_1=0.5L"

Let initial pressure be "P_1"

and Volume of Vessel "v_2=4.5L"

pressure of vessel "P_2=0.98 atm"

Using Boyle's law we have,

"P_1V_1=P_2V_2"

"P_1\\times 0.5=0.98\\times 4.5\\\\\\Rightarrow P_1=8.82atm"

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