Answer to Question #176775 in General Chemistry for Tia Fountain

Question

The pressure of a sample of helium in a 1.50-L container is 0.88 atm. What is the new pressure if the sample is placed in a 2.00 L container?

Answer 1

P1V1 = P2V2

0.88 atm × 1.50L = 2.00L × X

1.32 = 2.00X

X = 1.32/2.00

= 0.66 atm