Answer to Question #176769 in General Chemistry for Ruby

Question

What volume at STP would 4.55 × 1025 molecules (particles) of oxygen gas occupy? Show all work.

Answer 1

Number of moles ;

$=4.055×10 ^{25}×\frac {1 mole} {6.022×10 ^{23}}$

=67.34moles.

$=67.34moles ×\frac {22.4L}{1 mole}$

=$1,508.34L$