Answer to Question #176712 in General Chemistry for Jordan Sperl

Question

The pH of a 0.15 M solution of H2CO3 is 5.52 please find the following: Show all work

1. The first ionization expression 

• H2CO3 + H2O ---->  H+  + HCO3-  

1. The Ka expression

• Ka= [H+][HCO3-]/ [H2CO3]

1. Solve for Ka

• 105.52 = 

1. Solve for Kb

Answer 1

2.51 × 10^24/ 6.022 × 10^23

= 0.4168 × 10^1 = 4.618mol Pb

= 4.618 × (207.2 g/mol)

= 956.8496g of lead metal