Given the values P = 5.68 atm, V = 343 mL, n = 0.31 mol, for those of the gas variables, find T. Answer in units of ◦C
PV= nRT
5.68atm × 0.343 L = 0.31 mol × 0.0821 L/ atm/mol/K
1.94824 = 0.02541T
= 76.6721 K
= 76.6721 - 273 = -196.3279
= -196.33°C
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