What is the [H+] of a solution that has a pH of 3.5?
[H+] = 4.47 × 10^-3.35
The PH of a solution is found by
PH = -log [H+]
[H+] = 10 ^-PH
[H+] = 10^-3.35
= 4.47 × 10^-4 M
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