Answer to Question #175083 in General Chemistry for Alina

Question

The half-life of 27Mg is 9.50 min.

a) Initially there were 3.70 x 10^12 27Mg nuclei present. How many 27Mg nuclei are left 27.0 min later? Please give your answer to 2 significant figures.

b) Calculate the 27Mg activities (in Ci) at t=0 and t=27.0 min

Answer 1

a) $6.7×10^{11}$

b) At t=0;

$A=4.9×10 ^{9}sec^{-1}$

At t=0;

$A=7.7×10 ^{8}sec^{-1}$