Answer to Question #174630 in General Chemistry for Rebecca

General Chemistry

Question #174630

How many grams of BCl₃contains 0.83 x 10²³ molecules of BCl₃

Expert's answer

Molar Mass of BCl3 = 117.17 g/mol

6.022 × 10^23 = 117.17 g

1 molecule = 117/(6.022 × 10^23)

0.83× 10^ 23= (117.17 ×0.83× 10^23) /(6.022×10^23)

(117.17 × 0.83)/ 6.022 = 16.1493g

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