Answer to Question #172389 in General Chemistry for Julia

Question #172389

Lead (II) iodide, PbI2 has a Ksp = 7.1 x 10-9. Calculate the solubility (in g/L) of PbI2 in 0.40 M Pb(NO3)2 solution. [bonus 2] How many times is PbI2 more or less soluble in 0.40 M Pb(NO3)2 solution than in pure water?


1
Expert's answer
2021-03-17T06:42:20-0400

Solubility ="4.213\u00d710^{-4}M"


It would be twice more soluble than in pure water.


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