Question

Stacey performed a reaction that actually produced 3.94 mol of CO2.  Her teacher told her she should have gotten 4.19 moles of CO2 . Determine her percent yield.

Answer 1

Percent yield = ( Experimental yield ÷ Theoritical yield)100

%yield$=\frac{3.94}{4.19}× 100=94.03 percent$