Answer to Question #172359 in General Chemistry for Emily Ortiz

Question #172359

If you start with 43.8 grams of CaCO3, how many grams of ZnCO3 will be produced?


3 CaCO3 + Zn3(PO4)2 🡪 Ca3(PO4)2 + 3 ZnCO3


1
Expert's answer
2021-03-17T06:41:40-0400

54,9 grams


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