Answer to Question #172094 in General Chemistry for Marie

Question #172094

2NO(g)+Cl2​(g)→2NOCl(g)


Experiment [NO] (M) [Cl2] (M) Rate(M/s)

1 0.0300 0.0100 3.4 x 10-4

2 0.0150 0.0100 8.5 x 10-5

3 0.0150 0.0400 3.4 x 10-4


Determine the rate law and calculate the rate constant and determine the order of the reaction with respect to NO(g).


1
Expert's answer
2021-03-17T06:37:34-0400

For the order of NO, comparing 1 and 2

As the concentration doubles, the rate quadruples, therefore implying a second order in NO

For the order of Cl2, comparing 2 and 3, the rate quadruples as the concentration quadruples, implying a first order I'm Cl2

Rate = k[NO]2[Cl2]

Taking experiment 1

K = Rate /[NO]2[Cl2]

= 3.4×10-4/([0.03]2[0.01])

= 37.77 M-2s-1

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