Question

Calculate the molarity of 20.5 g sodium chloride (NaCl) compound with molar mass of 

58.44g/mole placed in 55.0 mL of total solution. 

Answer 1

Moles of NaCl = $\frac{20.5}{58.44}=0.35moles$

$55.0mL = \frac{55}{1000}=0.055 L$

Hence

$Molarity = \frac{0.35}{0.055}=6.36M$