Answer to Question #171686 in General Chemistry for Corey Pardy

Question #171686

calculate the mass of nickel(III) sulfate required to prepare 425mL of a 0.0289 mol/L solution


1
Expert's answer
2021-03-15T09:46:28-0400

no of mole = volume x concentration

= 0.425L x 0.0289M = 0.012 mole


mass = molar mass x no of mole

= 0.012 x 155 = 1.86g


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