Answer to Question #171534 in General Chemistry for Kaniya

Question

How many moles of aluminum phosphate are present in 100.0g?

Answer 1

aluminum phosphate

AlPO₄

100g

1 mol = 121.9529 g

What about 100g of AlPO₄

Therefore :

121.9529 g = 1 mol

100g = ?

(100)(1)/(121.9529 )

100/121.9529 =

= 0.8199887006Moles