Answer to Question #170970 in General Chemistry for Zayn Mace

General Chemistry

Question #170970

What is the temperature of a 3.5 mol of He gas contained in 34 L container with a pressure of 2.11 atm?

Expert's answer

"PV= n RT"

"T= \\frac{PV}{nR}"

P = 2.11 atm

n = 3.5

R = 0.0821 ( constant)

V = 34

"T=\\frac{2.11\u00d734}{3.5\u00d70.082}=249.97 K" or "-23.03\u00b0c"

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