Question

You make a solution containing 381.1 g of sucrose C12H22O11 dissolved in 750.g of water. What is the boiling point of the solution

Answer 1

$\Delta$T_b = iK_bm

K_b= 0.512 degrees

C12H22O11 = $(12×12)(22×1)(11×16)=342 g/m$

Mass of water in kg = $\frac{750}{1000}=0.75$

Boiling point of solution = $0.512(\frac{381.1}{342×0.75})=0.76$ degrees celsius