Answer to Question #170724 in General Chemistry for Shania

Question #170724

How many moles of sodium carbonate soluble are present in 400cm3 of sodium carbonate solution which has a concentration of 0.25 mol/dm3


1
Expert's answer
2021-03-15T09:07:00-0400

с (Na₂CO₃) = n(Na₂CO₃)/V(Na₂CO₃ solution);

n (Na₂CO₃) = c (Na₂CO₃) * V (Na₂CO₃ solution);

V = 400 cm3 = 0.4 dm3;

n =  0.25 mol/dm3 * 0.4 dm3 = 0.1 mole;

answer: 0.1 mole.


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment

Ask Your question

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS