Question

1. 2H₂ + O₂ ® 2H₂O

a.) How many moles of H₂ would be required to produce 8.21 moles of water?

 

          

 

b.) What mass of H₂O is formed when H₂ reacts with 57 g of O₂?

 

Answer 1

a) $=\frac{8.21 moles H_2O×2 mol H_2}{2 mol H_2O}$

$=8.21mol H_2$

b) The mol ratio between $O_2$ and $H_2O$ is 1:2, meaning there are 2 moles of water produced for every every 1 mole of Oxygen reacted with Hydrogen.

$=\frac{57g O_2} {32g/mol}=1.78mol O_2$

=2×1.78=3.56mol of water produced.

Since water has a molar Mass of 18g/mol

$=3.56 mol ×18g/mol$

=64.08g $H_2O$