Answer to Question #170261 in General Chemistry for Amy

Question

For the compound FeCl₃ , starting with 1.75 x 10²⁴ chloride ions: please keep answers to two places past decimal point.

how many formula units would be possible to make?

how many moles of the compound would be present?

how many grams would be present ?

Answer 1

No. Of molecules of FeCl₃= (17.5×10²³ )/ 3

= 5.83 ×10²³

No. Of units 1 unit contains 6 molecule of FeCl₃

=( 5.83 ×10²³ )/ 6 = 0.97 ×10²³

No of moles = (5.83 × 10²³ )/ (6.022×10²³)

= 0.96

Mass = 0.96 × 162.2 = 155.71g