Answer to Question #170094 in General Chemistry for David

Question #170094

Calculate the boiling point of 20% (mass fraction) glucose solution (K_b = 0.52).

Expert's answer

n=m/Mr = 20/180 = 0,111111111 moles.

m=moles of solute/kg of solvent=0,111111111/0.08 = 1,38888889 Molality

∆Tb= Kb x m x i = 0.52 x 1,38888889 x 1 = 0,722222223.

T=100 + 0,722222223 = 100,722222223 °©.

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