Answer to Question #170072 in General Chemistry for Toris

Question

How much total heat in calories is required to raise the temperature of 7.09 g of ice at −12.0°C to water vapor at 112°C?

Refer to the table below for relevant data::

Heat of vaporization = 540 cal/g

Specific heat of ice = 0.48 cal/g · °C

Specific heat of liquid water = 1.00 cal/ g · °C

Heat of fusion of ice = 80. cal/g

Specific heat of steam = 0.48 cal/g · °C

Total heat= ..........cal

Answer 1

Q=mc∆T = 7.09 x 4.18 x 124 = 3 674,8888 J = 877.73 Calories.