A sample of nitrogen occupies 11.2 liters under a pressure of 580 torr at 32◦C. What volume would it occupy at 32◦C if the pressure were increased to 810 torr?
pV=nRT.
n=pV/RT = 77.327 x 11.2/8.314 x 305 =
0,34153823 moles.
V=nRT/p= 0,34153823 x 8.314 x 305/107.991 = 8,01976457 L.
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