how many grams of fe2o3 are needed to produce 51.9 g of cao
Moles of Fe2O3 = 51.9 g / 159.69 g = 0.325moles
1 moles of Fe2O3 gives 1 moles of CaO
0.325 moles of Fe2O3 gives 0.325 moles of CaO
Gram of CaO = 0.325×56.077 = 18.22 g
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