What volume of a 0.526 M CaCl2 solution should be used to prepare a 346 mL solution that is 0.0431 molar?
M1 = 0.526M , V1 = ? , M2 = 0.0431M , V2 = 346ml
M1V1 = M2V2
0.526×V1 = 0.0431×346
V1 = 28.35ml
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment