Question

If 5.50 kJ if he is applied to a 0.5 85 MOL sample of solid copper at 25 Celsius what will the coppers final temperature be in Celsius the specific heat of solid copper is 0.385 J/G•K

Answer 1

$Q=mc\theta$

$1mol=65g$

$0.585moles=?$

$(\frac{65×0.585}{1})g=25.025g$

5.50=25.025g×0.385×(x-25)

5.50=9.634625x$-$ 246.865625

$\frac{246.8656}{9.634625}=\frac{9.64625x}{9.634625}$

$x=25.57°C$