Answer to Question #168471 in General Chemistry for gin

Question

What is the molality of a solution made by dissolving 50 g of acetic acid

(CH3COOH) in 950 g of ethanol.

Answer 1

Ans:- Molecular mass of $CH_3COOH$ is $60$ $\dfrac{g}{mol}$

Now find the moles of acetic acid

$\Rightarrow$ moles of acetic acid$=\dfrac{given mass}{molecular mass}$

$\Rightarrow$ $\dfrac{50}{60}=0.833mol$

Therefore Molality$=\dfrac{no. of moles of solute}{mass of solvent in (gm)}\times1000$

$\Rightarrow$ molality of acetic acid$=\dfrac{0.833}{950}\times1000=0.8771m$

Therefore molality of acetic acid in ethanol is $0.8771m$