Answer to Question #168417 in General Chemistry for Dawson

Question #168417

When 1 mol of CS2(l) forms from its elements at 1 atm and 25°C, 89.7 kJ is absorbed, and it takes 27.7 kJ to vaporize 1 mol of the liquid. How much heat is absorbed when 1 mol of CS2(g) forms from its elements at these conditions? Do not answer in scientific notation.



1
Expert's answer
2021-03-08T06:11:20-0500

Solution:

Use Hess's Law to find the answer:


"C_{graphite}(s)\\;+\\;2S(s)\\rightarrow\\;CS_2(l)\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\Delta H=89.7\\;(\\frac{kJ}{mole})"


"CS_2(l)\\rightarrow CS_2(g) \\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\; \\Delta H=27.7(\\frac{kJ}{mole})"


"C_{graphite}(s)+2S(s) \\rightarrow CS_2 (g) \\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\; \\Delta H=89.7+27.7=117.4 (\\frac{kJ}{mole})"



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