please with steps
NH4NO2 (s) = N2 (g) + H2O (g)
When a sample is decomposed in a test tube, 949 mL of wet N2(g) is collected over water at 26°C and 778 torr total pressure. How many grams of dry NH4NO2(s) were initially decomposed? The vapor pressure of water at 26°C is 25.2 torr.
1.find the amount of substance
"PV = nRT"
"0.990526712\\times0.949 = n\\times0.08206\\times299.15"
"0.94 = n\\times24.55"
"m=M\\times n=64.044\\times0.0383=2.45 g"