Answer to Question #167977 in General Chemistry for Jayla

Question

If you react .994 grams of iron (III) oxide with aluminum, what mass of iron (Fe) will be produced?

                                Fe2O3   +   Al   ®   Al2O3  +  F

Answer 1

Fe₂O₃ + 2Al = Al₂O₃ + 2Fe

The mass of iron produced equals:

m(Fe) = m(Fe₂O₃) × 2 × Mr(Fe) / Mr(Fe₂O₃) = 0.994 g × 2 × 55.845 g/mol / 159.69 g/mol = 0.695 g

Answer: 0.695 g