Answer to Question #167716 in General Chemistry for Skylar A Evans

Question #167716

Cu = 61.37% and O = 38.63%.

What will be the empirical formula based on these mass percent values?


1
Expert's answer
2021-03-01T02:37:54-0500

Let the numbers of Cu and O atoms in the empirical formula be x, y, respectively.

Atomic masses

Ar(Cu)=63.5

Ar(O)=16


"X:Y=\\omega(X)\/A(X):\\omega(Y)\/A(Y)"

"X:Y=(61.37\/63.5):(38.63\/16)"

"X:Y=0.97:2.4=1:2.5=2:5"

Empirical formula Cu2O5


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