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Answer to Question #167322 in General Chemistry for Jose Ulises Ramirez
Question #167322
A sample of an industrial waste water is analyzed and found to contain 44.9 ppb Mn2+. How many grams of manganese could be recovered from 1.17×103 kg of this waste water?
Expert's answer
44.9ppb = 44.9 microgram per Kg
Hence, 1Kg of waste water contains 44.9 microgram of Mn2+
1.17x10^3Kg of Waste water contains (44.9x1.17x10^3)
= 52533microgram
Converting microgram to grams, since the question requested for grams
= 52533x10^-9 = 5.2533 x 10^-5g
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