the molar enthalpy of combustion of ethanol (c2H5OH) is -1366.8kj/mol what is the enthalpy change when 10.00 grams of ethanol is combusted
n(C2H5OH)=m/M=10/46 = 0.2174 mol
H= (-1366.8)*0.2174 = -297.14 kJ
Answer: -297.14 kJ
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