Answer to Question #166871 in General Chemistry for hayden

Question #166871

if i have 3.7 moles of magnesium chloride reacting with excess potassium nitride , how many moles of each product are formed?


1
Expert's answer
2021-02-26T05:59:10-0500

Equation of reaction is

3MgCl2 + 2K3N=> 6KCl + Mg3N2


3moles of MgCl2 = 6moles of KCl

3.7moles of MgCl2 = (6x3.7)/3 moles of KCl

= 7.40 mol of KCl


For the second product

3mol of MgCl2 = 1mol of Mg3N2

3.7mol of MgCl2= (3.7 x 1)/3 moles of Mg3N2

= 1.23moles


Therefore 3.7 moles of MgCl2 will yield 7.40mol and 1.23mol of KCl and Mg3N2 respectively




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