Answer to Question #166526 in General Chemistry for Mark

Question

If 2.39 mol of ethane undergoes combustion how many moles of O2 are required answer in units of mol

Answer 1

The reaction of ethane combustion: is as following:

2C₂H₆ + 7O₂ = 4CO₂ + 6H₂O

Since the number of moles of ethane and oxygen must be equal, the number of moles of oxygen:

n(O₂) = (n(C₂H₆) × 7) / 2 = (2.39 mol × 7) / 2 = 8.365 mol

Answer: 8.365 mol