Answer to Question #166214 in General Chemistry for Savannah Oxenreider

Question

A 0.732 kg sample of gold is added to 100.0 mL of water. The density of gold is 19.32 g/mL. What is the final volume of water?

Answer 1

Mass of gold = 0.732 kg=732 gm

Density of gold=19.32g/ml

Now

$\Rightarrow$ volume of gold ($V_1$ ) =$\dfrac{mass}{density}$

$V_1$ = $\dfrac{732}{19.32}$

$V_1$ =37.89 ml

Volume of water given$(V_2)$ =100.0 ml

As water and gold do not mix with each otherso according to that the total volume

$\Rightarrow$ $V_1+V_2$

$\Rightarrow$ 37.89$+$ 100.0 ml

$\Rightarrow$ 137.89 ml