Answer to Question #166018 in General Chemistry for Marie

Question #166018

Calculate the mole fraction of each component of a solution containing 65g of ethanol (C2H6O) in 350g water.


1
Expert's answer
2021-02-24T03:37:50-0500

Moler mass of Ethanol ("C_2H_6O" )=46 g/mol

so moles of ethanol="\\dfrac{}{}" "\\dfrac{65}{46}" =1.41 moles


Now moles of water = "\\dfrac{350}{18}" =19.45 moles


Total moles = 1.41+19.45=20.86 moles


Mole fraction of ethanol= moles of ethnol/total moles

"\\Rightarrow" "\\dfrac{1.41}{20.86}" =0.067


Mole fraction of water=moles of water/total moles

"\\Rightarrow" "\\dfrac{19.45}{20.86}" =0.932


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